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6x^2-72x-66=0
a = 6; b = -72; c = -66;
Δ = b2-4ac
Δ = -722-4·6·(-66)
Δ = 6768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6768}=\sqrt{144*47}=\sqrt{144}*\sqrt{47}=12\sqrt{47}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-12\sqrt{47}}{2*6}=\frac{72-12\sqrt{47}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+12\sqrt{47}}{2*6}=\frac{72+12\sqrt{47}}{12} $
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